Question
0.23g of volatile liquid occupies 126.4 cc at 27°c and 760 mm pressure,calculate the molecular mass of the liquid
Answers
GPT 3.5
To find the molecular mass of the volatile liquid, we must first determine the number of moles of the substance present.
Using the Ideal Gas Law:
PV = nRT
Where:
P = pressure (760 mm)
V = volume (126.4 cc = 0.1264 L)
n = number of moles
R = ideal gas constant (0.0821 L atm/mol K)
T = temperature (27°C = 300 K)
Plugging in the values:
(760 mm) * (0.1264 L) = n * (0.0821 L atm/mol K) * (300 K)
96.384 = 24.63n
n = 3.92 moles
Next, we calculate the molecular mass of the substance using the formula:
Molecular mass = (mass of substance) / (moles of substance)
Given that the mass of the substance is 0.23g and the moles of substance is 3.92 moles:
Molecular mass = 0.23g / 3.92 moles
Molecular mass = 0.05867 g/mol
Therefore, the molecular mass of the volatile liquid is approximately 58.67 g/mol.
Using the Ideal Gas Law:
PV = nRT
Where:
P = pressure (760 mm)
V = volume (126.4 cc = 0.1264 L)
n = number of moles
R = ideal gas constant (0.0821 L atm/mol K)
T = temperature (27°C = 300 K)
Plugging in the values:
(760 mm) * (0.1264 L) = n * (0.0821 L atm/mol K) * (300 K)
96.384 = 24.63n
n = 3.92 moles
Next, we calculate the molecular mass of the substance using the formula:
Molecular mass = (mass of substance) / (moles of substance)
Given that the mass of the substance is 0.23g and the moles of substance is 3.92 moles:
Molecular mass = 0.23g / 3.92 moles
Molecular mass = 0.05867 g/mol
Therefore, the molecular mass of the volatile liquid is approximately 58.67 g/mol.