A ball is rolled horizontally off a table with an initial speed of 0.18 m/s. A stopwatch measures the ball’s trajectory time from table to the floor to be 0.30 s. What is the height of the table? Note: g = 9.8 m/s2 and air resistance is negligible.

Answer 1

To find the height of the table, we can use the kinematic equation for free fall:

H = vo*t + 0.5*a*t^2

Where:
H = height of the table
vo = initial velocity (0.18 m/s)
t = time of trajectory (0.30 s)
a = acceleration due to gravity (9.8 m/s^2)

Plugging in the values:

H = (0.18 m/s)(0.30 s) + 0.5*(9.8 m/s^2)*(0.30 s)^2
H = 0.054 m + 0.44 m
H = 0.494 m

Therefore, the height of the table is approximately 0.494 meters.