A load of 100N is applied to a wire, the extension is 0.01M calculate the energy stored in the wire

Answer 1

To calculate the energy stored in the wire, we can use the formula for elastic potential energy:

Elastic potential energy = 1/2 * k * x^2

where:
k = spring constant
x = extension

Given:
- Load applied = 100 N
- Extension = 0.01 m

First, we need to calculate the spring constant (k) using Hooke's Law:

k = F / x
k = 100 N / 0.01 m
k = 10000 N/m

Now, we can calculate the energy stored in the wire:

Elastic potential energy = 1/2 * 10000 N/m * (0.01 m)^2
Elastic potential energy = 1/2 * 10000 N/m * 0.0001 m^2
Elastic potential energy = 0.5 J

Therefore, the energy stored in the wire when a load of 100 N is applied and the extension is 0.01 m is 0.5 Joules.