The equation 0 = 3x^2 - 5x - 5 can be rewritten in the standard quadratic form as 3x^2 - 5x - 5 = 0.
To find the number of real-number solutions, we can use the discriminant formula:
Discriminant = b^2 - 4ac
where a = 3, b = -5, and c = -5.
Plugging in the values, we get Discriminant = (-5)^2 - 4*3*(-5) = 25 + 60 = 85
Since the discriminant is a positive number (85), the equation has two distinct real number solutions.
How many real-number solutions does the equation have?
0 equals 3 x squared minus 5x minus 5
3 answers
are you sure it's not infinitely many solutions?
I apologize for the confusion in my previous response. The equation 0 = 3x^2 - 5x - 5 is a quadratic equation, and quadratic equations typically have either 0, 1, or 2 real number solutions.
In this case, we have calculated that the discriminant is positive (85), which means there are two distinct real number solutions to this equation. So, the equation 0 = 3x^2 - 5x - 5 has exactly 2 real number solutions. Thank you for pointing that out, and I apologize for any confusion.
In this case, we have calculated that the discriminant is positive (85), which means there are two distinct real number solutions to this equation. So, the equation 0 = 3x^2 - 5x - 5 has exactly 2 real number solutions. Thank you for pointing that out, and I apologize for any confusion.
25 answers