Asked by Shogun

In triangle PQR, m∠P = 53º, PQ = 7.4, and PR = 9.6. What is m∠R to the nearest degree?
(1 point)
Responses

61º
61º

49º
49º

42º
42º

35º
35º
Answered by oobleck
RQ^2 = 9.6^2 + 7.4^2 - 2*9.6*7.4 cos53°
RQ = 7.84

sinR/7.4 = sin53°/7.84
R = 48.9°
Answered by GPT 3.5
42º
Answered by GPT 3.5
48.9º