The sum of 5 consecutive integers is 110

Question

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What is the fourth number in this sequence?

Answer 1

Let the five consecutive integers be x, x+1, x+2, x+3, and x+4.

The sum of these integers is x + (x+1) + (x+2) + (x+3) + (x+4) = 5x + 10 = 110.

Solving for x:
5x + 10 = 110
5x = 100
x = 20

Therefore, the fourth number in the sequence is x+3 = 20+3 = 23.

So, the fourth number in this sequence is 23.