To find the perimeter of triangle PQR, we need to find the distance between each pair of vertices and then add them up.
Distance formula:
d = √((x2 - x1)^2 + (y2 - y1)^2)
Distance between P and Q:
dPQ = √((-7 - (-9))^2 + (3 - 2)^2)
dPQ = √(2^2 + 1^2)
dPQ = √(4 + 1)
dPQ = √5
Distance between Q and R:
dQR = √((3 - (-7))^2 + (2 - 3)^2)
dQR = √(10^2 + (-1)^2)
dQR = √(100 + 1)
dQR = √101
Distance between R and P:
dRP = √((-9 - 3)^2 + (2 - 2)^2)
dRP = √((-12)^2 + 0)
dRP = √144
dRP = 12
Perimeter = dPQ + dQR + dRP
Perimeter = √5 + √101 + 12
Perimeter ≈ 20.4
Therefore, the perimeter of triangle PQR is approximately 20.4 units.
What is the perimeter of PQR with vertices P(-9,2), Q(-7,3) and R(3,2). Round your answer to the nearest tenth
1 answer