Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.

Question

x^2 + 3 = -4x
A. 1, 3
B. -1, -3
C. 1, -3
D. -1, 3

Answer 1

First, rewrite the equation in standard form by moving all terms to one side:

x^2 + 4x + 3 = 0

Now, identify a=1, b=4, and c=3 in the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / 2a

Plug in the values:

x = (-4 ± √(4^2 - 4(1)(3))) / 2(1)
x = (-4 ± √(16 - 12)) / 2
x = (-4 ± √4) / 2
x = (-4 ± 2) / 2

Now solve for x:

x = (-4 + 2) / 2 = -2 / 2 = -1
x = (-4 - 2) / 2 = -6 / 2 = -3

Thus, the solutions are x = -1 and x = -3. The answer is B. -1, -3.