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A race driver has made a pit stop to refuel. After refueling, he starts from rest and leaves the pit area with an acceleration...Question
A race driver has made a pit stop to refuel. After refueling, he starts from rest and leaves the pit area with an acceleration whose magnitude is 5.8 m/s2; after 3.6 s he enters the main speedway. At the same instant, another car on the speedway and traveling at a constant velocity of 67.4 m/s overtakes and passes the entering car. The entering car maintains its acceleration. How much time is required for the entering car to catch up with the other car?
Answers
Damon
how fast is he going after 3.6 seconds
at = 5.8 * 3.6 = 20.88
so
starting new t = 0 at 20.88 m/s
v = 20.88 + 5.8 t
d = 20.88 t + (5.8/2) t^2
same distance as the other car going 67.4
so
67.4 t = 20.88 t + (5.8/2)t^2
solve quadratic, use reasonable of two answers.
at = 5.8 * 3.6 = 20.88
so
starting new t = 0 at 20.88 m/s
v = 20.88 + 5.8 t
d = 20.88 t + (5.8/2) t^2
same distance as the other car going 67.4
so
67.4 t = 20.88 t + (5.8/2)t^2
solve quadratic, use reasonable of two answers.
Anonymous
67