Question

On a hot day (40°C) at standard pressure, a tree takes in 59.87g of carbon dioxide. What volume of carbon dioxide is removed from the

Answer 1

To calculate the volume of carbon dioxide removed from the air, we need to use the ideal gas law equation:

PV = nRT

where:
P = pressure (1 atm)
V = volume
n = number of moles of gas
R = ideal gas constant (0.0821 L.atm/mol.K)
T = temperature in Kelvin

First, let's convert the mass of carbon dioxide into moles. The molar mass of carbon dioxide (CO2) is approximately 44.01 g/mol.

Number of moles (n) = mass / molar mass
n = 59.87g / 44.01 g/mol
n = 1.36 moles

Next, we need to convert the temperature from Celsius to Kelvin:
T(K) = T(°C) + 273.15
T = 40°C + 273.15
T = 313.15 K

Now we can plug in the values into the ideal gas law equation:

PV = nRT
V = nRT / P
V = (1.36 moles)(0.0821 L.atm/mol.K)(313.15 K) / 1 atm
V ≈ 35.4 L

Therefore, approximately 35.4 liters of carbon dioxide are removed from the air by the tree on a hot day at standard pressure.