To simplify the given expression:
5^2𝑥+1 + 2.5^2𝑥-1 / 2.5^2𝑥
First, we can rewrite 2.5 as 5/2:
5^2𝑥+1 + (5/2)^2𝑥-1 / (5/2)^2𝑥
Now we can use the properties of exponents to simplify:
(5^(2𝑥) * 5^1 + 5^(2𝑥) * (5/2)^(-1)) / (5/2)^(2𝑥)
(5^(2𝑥+1) + 5^(2𝑥) * (2/5)^(1)) / (5/2)^(2𝑥)
(5^(2𝑥+1) + 5^(2𝑥) * 2/(5^2)) / (5/2)^(2𝑥)
(5^(2𝑥+1) + 5^(2𝑥) * 2/25) / (5/2)^(2𝑥)
Now we can simplify further if needed, but this is the fully simplified form of the expression.
2.1
Simplify fully, without the use of a calculator:
2.1.2
5^2𝑥+1+2.5^2𝑥−1 /2.5^2𝑥
(3)
3 answers
how can you call that final mess "simplified"?
I suspect the question has been mangled, since
(5/2)^2𝑥-1 / (5/2)^2𝑥 = 5^-1 = 1/5
so the whole thing is just
5^2𝑥+1 + 1/5
I doubt this was the original intent
I suspect the question has been mangled, since
(5/2)^2𝑥-1 / (5/2)^2𝑥 = 5^-1 = 1/5
so the whole thing is just
5^2𝑥+1 + 1/5
I doubt this was the original intent
Apologies for the confusion in my previous response. Let me simplify the expression correctly.
Given expression:
(5^2𝑥+1 + 2.5^2𝑥-1) / 2.5^2𝑥
Rewriting the expression with 2.5 as 5/2:
(5^(2𝑥+1) + (5/2)^(2𝑥-1)) / (5/2)^(2𝑥)
Using the property of exponents, we get:
(5^(2𝑥) * 5^1 + (5/2)^(2𝑥) / (5/2)^(2𝑥)
(5^(2𝑥) * 5 + (5/2)^(2𝑥) / (5/2)^(2𝑥)
(25 * 5^2𝑥 + (5/2)^(2𝑥) / (5/2)^(2𝑥)
(25 * 5^2𝑥 + 2^(2𝑥) * 5^(-2𝑥))
(25 * 5^(2𝑥) + 1) / 5
25 * 5^(2𝑥) / 5 + 1 / 5
5^(2𝑥) * 5 + 1 / 5
25 * 5 + 1 / 5
125 + 1 / 5
126 / 5
So, the simplified expression is 126/5. Thank you for catching the error and helping with the correction.
Given expression:
(5^2𝑥+1 + 2.5^2𝑥-1) / 2.5^2𝑥
Rewriting the expression with 2.5 as 5/2:
(5^(2𝑥+1) + (5/2)^(2𝑥-1)) / (5/2)^(2𝑥)
Using the property of exponents, we get:
(5^(2𝑥) * 5^1 + (5/2)^(2𝑥) / (5/2)^(2𝑥)
(5^(2𝑥) * 5 + (5/2)^(2𝑥) / (5/2)^(2𝑥)
(25 * 5^2𝑥 + (5/2)^(2𝑥) / (5/2)^(2𝑥)
(25 * 5^2𝑥 + 2^(2𝑥) * 5^(-2𝑥))
(25 * 5^(2𝑥) + 1) / 5
25 * 5^(2𝑥) / 5 + 1 / 5
5^(2𝑥) * 5 + 1 / 5
25 * 5 + 1 / 5
125 + 1 / 5
126 / 5
So, the simplified expression is 126/5. Thank you for catching the error and helping with the correction.