:To standardize an HCl solution, you put 50.00 mL of it in a flask with a fewdrops of indicator and put 0.1524 M NaOH in a buret. The buret reads 0.55 mL at the start and 33.87 mL at the end point. Find the molarity of the HCl solution?

Answer 1

To find the molarity of the HCl solution, we will use the concept of titration.

Step 1: Calculate the moles of NaOH used in the titration.

Volume of NaOH used = 33.87 mL - 0.55 mL = 33.32 mL = 0.03332 L

Moles of NaOH = Molarity x Volume
Moles of NaOH = 0.1524 mol/L x 0.03332 L
Moles of NaOH = 0.00507 mol

Step 2: Calculate the moles of HCl in the flask.

Since HCl reacts in a 1:1 ratio with NaOH, the moles of HCl will also be 0.00507 mol.

Step 3: Calculate the molarity of the HCl solution.

Molarity of HCl = Moles of HCl / Volume of HCl solution
Volume of HCl solution = 50.00 mL = 0.05000 L

Molarity of HCl = 0.00507 mol / 0.05000 L
Molarity of HCl = 0.1014 M

Therefore, the molarity of the HCl solution is 0.1014 M.