a. Distance-time graph:
The graph starts at point A (Sunyani), then the driver travels for 30 minutes to point B, rests for 30 minutes at Bechem, continues to Kumasi (point C) in 60 minutes, then returns to Sunyani in 120 minutes.
b.
I. The driver stayed at Bechem for 30 minutes.
II. The distance from Bechem to Kumasi is 40km (given).
III. Average speed from Bechem to Kumasi:
Average speed = total distance / total time taken
Average speed = 40km / 60 minutes = 0.67 km/minute or 40 km/h
IV. Average speed on the return journey:
Average speed = total distance / total time taken
Average speed = 40km / 120 minutes = 0.33 km/minute or 20 km/h
V. Average speed for the whole journey:
Total distance = 2 * 40km = 80km
Total time = 30 + 30 + 60 + 120 = 240 minutes
Average speed = total distance / total time taken
Average speed = 80km / 240 minutes = 0.33 km/minute or 20 km/h.
A driver travels from sunyani to Kumasi the distance between the two cities is 40km from sunyani 30 minutes later, he continued journey to Kumasi in 60minutes. After resting for 30 minutes he makes a return journey to sunyani in 120minutes.
a. Draw a distance time graph for the above information. b. From the graph,
I. How long did the driver stay at Bechem.
Ii. How far is it from Bechem to kumasi.
iii. find the average speed from Bechem to kumasi.
iv. average speed on return journey.
v. average speed for the whole journey
1 answer
1 answer