Asked by Anonymous
What is the kinetic energy of the emitted electrons when cesium is exposed to UV rays of frequency 1.5*10^{15}Hz?
Answers
Answered by
bobpursley
Find the energy of the photon, subtract the work function of Cesium, then convert the remainder to KE.
http://hyperphysics.phy-astr.gsu.edu/HBASE/Tables/photoelec.html
http://hyperphysics.phy-astr.gsu.edu/HBASE/Tables/photoelec.html
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