Asked by Anonymous

What is the kinetic energy of the emitted electrons when cesium is exposed to UV rays of frequency 1.5*10^{15}Hz?
Answered by bobpursley
Find the energy of the photon, subtract the work function of Cesium, then convert the remainder to KE.
http://hyperphysics.phy-astr.gsu.edu/HBASE/Tables/photoelec.html