The number of marbles of different colors stored in a hat is listed below:

4 red marbles
10 green marbles
7 blue marbles
Without looking in the hat, Dan takes out a marble at random. He replaces the marble and then takes out another marble from the hat. What is the probability that Dan takes out a blue marble in both draws? (5 points)

fraction 2 over 21

fraction 1 over 9

fraction 1 over 2

fraction 2 over 3

1 answer

The probability of taking out a blue marble on the first draw is 7/21. Since Dan replaces the marble, the probability of taking out a blue marble on the second draw is also 7/21.

Therefore, the probability of Dan taking out a blue marble in both draws is:

(7/21) * (7/21) = 49/441 = 1/9

So, the correct answer is:

fraction 1 over 9