P( bouncy balls or yo-yo

Answer 1

) = P(bouncy balls) + P(yo-yo)

Since bouncy balls and yo-yo are two disjoint events, we can simply add their individual probabilities.

P(bouncy balls) = 0.6
P(yo-yo) = 0.4

Therefore, P(bouncy balls or yo-yo) = 0.6 + 0.4 = 1.

So the probability of selecting either a bouncy ball or a yo-yo is 1 or 100%.