The probability of Dan taking out a blue marble on the first draw is 7/21. Since he replaces the marble after the first draw, the probability of him taking out a blue marble on the second draw is also 7/21.
Therefore, the probability that Dan takes out a blue marble in both draws is (7/21) * (7/21) = 49/441 = 1/9.
So, the correct answer is fraction 1 over 9.
The number of marbles of different colors stored in a hat is listed below:
4 red marbles
10 green marbles
7 blue marbles
Without looking in the hat, Dan takes out a marble at random. He replaces the marble and then takes out another marble from the hat. What is the probability that Dan takes out a blue marble in both draws fraction 2 over 21
fraction 1 over 9
fraction 1 over 2
fraction 2 over 3
1 answer