Let the son's age be x years and the man's age be y years.
According to the given information:
1. y = 4x (man is 4 times as old as his son)
2. y - 6 = 10(x - 6) (6 years ago he was 10 times as old)
Substitute the value of y from equation 1 into equation 2:
4x - 6 = 10(x - 6)
4x - 6 = 10x - 60
6 = 6x - 60
6x = 66
x = 11
Substitute x = 11 into equation 1:
y = 4(11)
y = 44
Therefore, the son is 11 years old and the man is 44 years old.
At the present time a man is 4 times as old as his son 6 years ago he was 10 times as old find their present ages
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