Asked by Cal
A proton is released at the origin in a constant electric field of 850 N/C acting in the positive x-direction. Find the change in the electric potential energy associated with the proton after it travels to x = 2.5 m.
Answers
Answered by
drwls
The electric potential decreases by an amount q E * (2.5 m)
q is the electron charge with a plus sign (for the proton charge), in Coulombs. E is the electric field strength, in N/C.
The Potential Energy decreases because the field does work on the proton when moving in the +x axis direction
q is the electron charge with a plus sign (for the proton charge), in Coulombs. E is the electric field strength, in N/C.
The Potential Energy decreases because the field does work on the proton when moving in the +x axis direction
Answered by
er
45
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.