Asked by Fred
Platinum has a face-centered cubic crystal structure and a density of 21.5 g/cm3. What is the radius of the platinum atom?
Answers
Answered by
DrBob222
The fcc has 4 atoms/unit cell.
Mass of 1 atom Pt = 195.08/6.02 x 10^23.
Mass of unit cell is 4 times that.
Then m = volume x density. You know density and mass, calculate volume of unit cell. From volume = a<sup>3</sup> you can calculate a (the length of the side).
For a fcc unit cell, 4*radius = a*2<sup>1/2</sup>. You know a and that allows you to calculate radius.
Post your work if you get stuck.
You know
Mass of 1 atom Pt = 195.08/6.02 x 10^23.
Mass of unit cell is 4 times that.
Then m = volume x density. You know density and mass, calculate volume of unit cell. From volume = a<sup>3</sup> you can calculate a (the length of the side).
For a fcc unit cell, 4*radius = a*2<sup>1/2</sup>. You know a and that allows you to calculate radius.
Post your work if you get stuck.
You know
Answered by
Anonymous
98
Answered by
Anonymous,
is not 98. try 139
There are no AI answers yet. The ability to request AI answers is coming soon!