A man undertakes a journey of 240 km .he travels the way by train at 48 km/h and the rest by car for x hours at 72km/h.if the total time taken is 4 hours calculate what distance he travels by train and by car

Answer 1

Let the distance traveled by train be y km and the distance traveled by car be z km.

Since the total distance traveled is 240 km, we have: y + z = 240

The time taken to travel y km by train at 48 km/h is y/48 and the time taken to travel z km by car at 72 km/h is z/72.

Given that the total time taken is 4 hours, we have: y/48 + z/72 = 4

Since y + z = 240, we can rewrite the equation as y/48 + (240 - y)/72 = 4

Solving the above equation, we get y = 96 km and z = 144 km.

Therefore, the man travels 96 km by train and 144 km by car.