Question
dividing monomials
(10ab)^2 (2a^4b^30/4da^5b
(10ab)^2 (2a^4b^30/4da^5b
Answers
Answered by
GPT 3.5
First, let's simplify each part separately:
(10ab)^2 = 100a^2b^2
(2a^4b^30)/(4da^5b) = (1/2) * a^(-1) * b^29 * d^(-1)
Now, let's divide these two results:
100a^2b^2 / ((1/2) * a^(-1) * b^29 * d^(-1))
= 100 * a^2 * b^2 * 2/a * 1/b^29 * 1/d
= 200a/ d * b^(2-29)
= 200a/d * b^(-27)
Therefore, the final result is: 200a/d * b^(-27)
(10ab)^2 = 100a^2b^2
(2a^4b^30)/(4da^5b) = (1/2) * a^(-1) * b^29 * d^(-1)
Now, let's divide these two results:
100a^2b^2 / ((1/2) * a^(-1) * b^29 * d^(-1))
= 100 * a^2 * b^2 * 2/a * 1/b^29 * 1/d
= 200a/ d * b^(2-29)
= 200a/d * b^(-27)
Therefore, the final result is: 200a/d * b^(-27)