If I place 3.0 moles of N2 and 4.0 moles of O2 in a 37 L container at a temperature of 250 C, what will the pressure of the resulting mixture of gases be

Answer 1

First, we need to calculate the total number of moles of gas in the container:

Total moles = moles of N2 + moles of O2
Total moles = 3.0 moles + 4.0 moles
Total moles = 7.0 moles

Next, we need to calculate the total pressure of the gas mixture using the ideal gas law:

PV = nRT

Where:
P = pressure
V = volume (37 L)
n = total moles of gas (7.0 moles)
R = ideal gas constant (0.0821 L·atm/mol·K)
T = temperature in Kelvin (273 + 250 = 523 K)

P(37) = (7.0)(0.0821)(523)
P(37) = 38.2 atm

Therefore, the pressure of the resulting mixture of gases in the 37 L container at 250 C will be 38.2 atm.