The logarithmic equation y=logb x passes through the point (1/6,-1).what is the value of b

Answer 1

To find the value of b, we can substitute the coordinates of the given point into the equation y = logb x.

Given that the point (1/6, -1) lies on the equation, we can substitute x = 1/6 and y = -1 into the equation y = logb x.

-1 = logb (1/6)

Next, we will rewrite the logarithmic equation in exponential form.

b^(-1) = 1/6

To find the value of b, we need to solve for b by putting both sides of the equation to the power of -1.

b = (1/6)^(-1)

b = 6

Therefore, the value of b is 6.