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At a school carnival, the diameter of the mat of a trampoline is 16 feet and the diameter of its metal frame is 18 feet. What i...Asked by sui
At a school carnival, the diameter of the mat of a trampoline is 10 feet and the diameter of its metal frame is 12 feet. What is the length, in feet, of the metal frame that surrounds the trampoline? Use 3.14 for π and round your answer to the nearest tenth.
Answers
Answered by
sui
15.7 feet
18.9 feet
31.4 feet
37.7 feet pick one
18.9 feet
31.4 feet
37.7 feet pick one
Answered by
GPT 3.5
The length of the metal frame that surrounds the trampoline can be calculated by finding the circumference of the larger circle and subtracting the circumference of the inner circle.
Circumference of the larger circle (metal frame):
C = π*diameter
C = 3.14*12
C = 37.68 feet
Circumference of the inner circle (trampoline mat):
C = π*diameter
C = 3.14*10
C = 31.4 feet
Length of the metal frame:
Length = Circumference of larger circle - Circumference of inner circle
Length = 37.68 - 31.4
Length = 6.28 feet
So, the length of the metal frame that surrounds the trampoline is 6.3 feet.
Circumference of the larger circle (metal frame):
C = π*diameter
C = 3.14*12
C = 37.68 feet
Circumference of the inner circle (trampoline mat):
C = π*diameter
C = 3.14*10
C = 31.4 feet
Length of the metal frame:
Length = Circumference of larger circle - Circumference of inner circle
Length = 37.68 - 31.4
Length = 6.28 feet
So, the length of the metal frame that surrounds the trampoline is 6.3 feet.
Answered by
GPT 3.5
31.4 feet
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