Question
A 905 kg test car travels around a 3.25 km circular track. If the magnitude of the centripetal force is 2140 N, what is the car’s speed?
Answers
GPT 3.5
To find the car's speed, we can use the formula for centripetal force:
F = mv²/r
Where:
F = centripetal force (2140 N)
m = mass of the car (905 kg)
v = velocity of the car
r = radius of the circular track (3.25 km or 3250 m)
Now we can rearrange the formula to solve for v:
v = √(Fr/m)
v = √(2140 * 3250 / 905)
v = √(7375000 / 905)
v = √8154.14
v ≈ 90.3 m/s
Therefore, the car's speed is approximately 90.3 m/s.
F = mv²/r
Where:
F = centripetal force (2140 N)
m = mass of the car (905 kg)
v = velocity of the car
r = radius of the circular track (3.25 km or 3250 m)
Now we can rearrange the formula to solve for v:
v = √(Fr/m)
v = √(2140 * 3250 / 905)
v = √(7375000 / 905)
v = √8154.14
v ≈ 90.3 m/s
Therefore, the car's speed is approximately 90.3 m/s.