the circumference of the base of a cylindrical tank isqqcm. the height of a tank is 3m more than6 times the base radius.calculate the

Question

a. radius
b. height
c. volume of the tank

Answer 1

a. Let the radius of the base be r cm.
The circumference of the base of the cylindrical tank is 2πr.
Given that 2πr = 88 cm.
Therefore, r = 88 / 2π cm ≈ 14 cm.

b. Let the height of the tank be h m.
Given that the height of the tank is 3 m more than 6 times the base radius:
h = 6r + 3
Substitute the value of r:
h = 6(14) + 3
h = 84 + 3
h = 87 m

c. The volume of a cylindrical tank is given by V = πr^2h.
Substitute the values of r and h:
V = π(14)^2(87)
V = 61578π cm³ ≈ 193239.75 cm³

Therefore,
a. The radius of the base is approximately 14 cm.
b. The height of the tank is 87 m.
c. The volume of the tank is approximately 193239.75 cm³.