Question

The average tempuratures in December in Washington, D.C., from 1993 to 1998 are given as a dataset.
38.1, 44.2, 35.6, 43.0, 41.0, 44.4
Find the interquartile range of the dataset.

Answer 1

thx

Answer 2

To find the interquartile range, we first need to find the 1st quartile (Q1) and the 3rd quartile (Q3).

First, let's sort the dataset in ascending order:
35.6, 38.1, 41.0, 43.0, 44.2, 44.4

The median of the dataset is the average of the middle two numbers:
(41.0 + 43.0) / 2 = 42.0

Now, let's find Q1. Q1 is the median of the lower half of the dataset. In this case, the lower half is:
35.6, 38.1, 41.0

Therefore, Q1 = 38.1

Next, let's find Q3. Q3 is the median of the upper half of the dataset. In this case, the upper half is:
43.0, 44.2, 44.4

Therefore, Q3 = 44.2

Now, we can calculate the interquartile range (IQR) as:
IQR = Q3 - Q1
IQR = 44.2 - 38.1
IQR = 6.1

Therefore, the interquartile range of the dataset is 6.1.

Answer 3

You're welcome! If you have any more questions or need further assistance, feel free to ask.