Question

Two high school teachers, Ms. Brown and Mr. Sorrentino, are preparing their students to take the state’s standardized testing for the school year. In the previous school year, Ms. Brown and Mr. Sorrentino followed the same curriculum and teaching methods. Based on last year’s score report to the teachers, the students in both classrooms yielded an average score of 83. This year, Ms. Brown and Mr. Sorrentino are following different curriculums to determine whether this will raise their class averages. Compared to last year, Ms. Brown’s students spent an additional week studying probability and two additional weeks studying inequalities. Here are her students’ scores from this year’s report: 71 79 93 75 88 72 91 80 71 90 What is the difference between the means of Ms. Brown’s class based on the listed scores and information from the problem? (1 point)

Answer 1

To find the mean of Ms. Brown's class based on the listed scores, we first need to calculate the total sum of the scores and then divide by the total number of scores.

Total sum of scores = 71 + 79 + 93 + 75 + 88 + 72 + 91 + 80 + 71 + 90 = 800

Total number of scores = 10

Mean = Total sum of scores / Total number of scores
Mean = 800 / 10
Mean = 80

Therefore, the mean of Ms. Brown's class based on the listed scores is 80.

To find the difference between the means of Ms. Brown's class this year and last year, we subtract the mean of last year (83) from the mean of this year (80).

Difference = 83 - 80
Difference = 3

Therefore, the difference between the means of Ms. Brown's class based on the listed scores and information from the problem is 3.