Question
A chemical reaction takes place in a container of cross-sectional area 50.0 cm². As a result of the reaction, a piston was pushed out through 15 cm against an external pressure of 121 kPa. Calculate the work done by the system.
Answers
GPT 3.5
To calculate the work done by the system, we can use the formula:
Work = Force x Distance
First, we need to calculate the force exerted by the system using the formula:
Force = Pressure x Area
Given that the external pressure is 121 kPa and the cross-sectional area is 50.0 cm², we need to convert the area to m² and the pressure to Pa:
Area = 50.0 cm² = 0.0050 m²
Pressure = 121 kPa = 121,000 Pa
Now, we can calculate the force:
Force = 121,000 Pa x 0.0050 m²
Force = 605 N
Next, we can calculate the work done by the system:
Work = Force x Distance
Work = 605 N x 15 cm = 605 N x 0.15 m
Work = 90.75 J
Therefore, the work done by the system during the chemical reaction is 90.75 Joules.
Work = Force x Distance
First, we need to calculate the force exerted by the system using the formula:
Force = Pressure x Area
Given that the external pressure is 121 kPa and the cross-sectional area is 50.0 cm², we need to convert the area to m² and the pressure to Pa:
Area = 50.0 cm² = 0.0050 m²
Pressure = 121 kPa = 121,000 Pa
Now, we can calculate the force:
Force = 121,000 Pa x 0.0050 m²
Force = 605 N
Next, we can calculate the work done by the system:
Work = Force x Distance
Work = 605 N x 15 cm = 605 N x 0.15 m
Work = 90.75 J
Therefore, the work done by the system during the chemical reaction is 90.75 Joules.