To solve this problem, we can use the combined gas law equation:
(P1/T1) = (P2/T2)
Where:
P1 = initial pressure = 760. mmHg
T1 = initial temperature = 100 °C = 373 K (273 K is added to convert from Celsius to Kelvin)
P2 = final pressure
T2 = final temperature = 150 °C = 423 K
Plugging in the values:
(760 mmHg / 373 K) = (P2 / 423 K)
Solving for P2:
P2 = (760 mmHg * 423 K) / 373 K
P2 = 861.76 mmHg
Therefore, the final pressure of the steam in the pressure cooker when the temperature is increased to 150 °C is approximately 862 mmHg.
A pressure cooker is used to cook food in a closed pot. By heating the contents of a pressure cooker at constant volume, the pressure increases. If the steam
inside the pressure cooker is initially at 100. °C and 760. mmHg, what is the final pressure (in mmHg) of the steam if the temperature is increased to 150. C?
Be sure your answer has the correct number of significant figures.
mmHg
1 answer