Question

80. The concentration and density of commercial HCl are 11.8 M 1.190 mg/L respectively. 
Calculate the molality of HCl.
A. 11.8 m B. 18.2 m C. 15.5 m D. 36.0 m

Answer 1

To find the molality of HCl, we need to first calculate the molarity in terms of mol/kg of solvent.

Molarity (M) = 11.8 mol/L
Density = 1.190 g/mL = 1.190 g/cm^3 = 1.190 mg/L = 1.190 g/L = 1.190 kg/L

Now, we need to convert the density from mg/L to kg/L:

1.190 mg/L = 0.00119 g/L = 0.00119 kg/L

Now, let's calculate the molality of HCl:

Molality (m) = moles of solute / kg of solvent
Molality = 11.8 mol/1 kg = 11.8 m

Therefore, the molality of HCl is 11.8 m.

The correct answer is A. 11.8 m.