The concentration of urea (CH4N2O) in a sample of urine is 8.8

Question

number of significant figures.
Note: Reference the SI prefixes table for additional information.

Part 1 of 2

. The molar mass of urea is 60.05
L

g
mol

Be sure each of your answer entries has the correct

What is the

weight
volume

percent concentration of urea in the urine?

%

urea

What is the molarity of urea in the urine?

Answer 1

To find the weight/volume percent concentration of urea in the urine, we need to use the formula:

Weight/volume % = (mass of solute / volume of solution) x 100

Since the concentration of urea in the urine is 8.8 g/L, we can calculate the weight/volume percent as:

Weight/volume % = (8.8 g / 1000 mL) x 100 = 0.88%

Therefore, the weight/volume percent concentration of urea in the urine is 0.88%.

To find the molarity of urea in the urine, we need to first calculate the number of moles of urea present in 1 L of urine. The molarity (M) is given by:

Molarity = (moles of solute / volume of solution in L)

Since the molar mass of urea is 60.05 g/mol, the number of moles of urea in 1 L of urine can be calculated as:

moles = 8.8 g / 60.05 g/mol = 0.1467 mol

Therefore, the molarity of urea in the urine is:

Molarity = 0.1467 mol / 1 L = 0.1467 M

So, the molarity of urea in the urine is 0.1467 M.