Calculate the pOH of 0.200 M aqueous NaOH at 25°C.

Question

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1 point
6
0.699
8
13.3

Answer 1

The pOH is calculated by taking the negative logarithm of the hydroxide ion concentration:

pOH = -log[OH-]
pOH = -log(0.200)
pOH = -(-0.699) (since log(0.200) is approximately -0.699)
pOH ≈ 0.699

Therefore, the pOH of 0.200 M aqueous NaOH at 25°C is approximately 0.699.