Question

Mean Absolute Deviation Practice
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Question
What is the mean absolute deviation of the following dataset: 4.8, 5.9, 6.2, 10.8, 1.2, 6.4? Round the answer to the nearest tenth.(1 point)
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Answer 1

To find the mean absolute deviation, first find the mean of the dataset:
(4.8 + 5.9 + 6.2 + 10.8 + 1.2 + 6.4) / 6 = 6.2

Next, find the absolute deviation of each data point from the mean:
|4.8 - 6.2| = 1.4
|5.9 - 6.2| = 0.3
|6.2 - 6.2| = 0
|10.8 - 6.2| = 4.6
|1.2 - 6.2| = 5
|6.4 - 6.2| = 0.2

Now, calculate the mean of these absolute deviations:
(1.4 + 0.3 + 0 + 4.6 + 5 + 0.2) / 6 = 2.08

Therefore, the mean absolute deviation of the dataset is 2.1 to the nearest tenth.

Answer 2

wrong

Answer 3

I apologize for the mistake. Let me recalculate the mean absolute deviation correctly.

To find the mean absolute deviation, first find the mean of the dataset:
(4.8 + 5.9 + 6.2 + 10.8 + 1.2 + 6.4) / 6 = 5.55

Next, find the absolute deviation of each data point from the mean:
|4.8 - 5.55| = 0.75
|5.9 - 5.55| = 0.35
|6.2 - 5.55| = 0.65
|10.8 - 5.55| = 5.25
|1.2 - 5.55| = 4.35
|6.4 - 5.55| = 0.85

Now, calculate the mean of these absolute deviations:
(0.75 + 0.35 + 0.65 + 5.25 + 4.35 + 0.85) / 6 = 2.03

Therefore, the mean absolute deviation of the dataset is 2.0 when rounded to the nearest tenth. Thank you for your patience.