Question

volume
- percent concentration of ethanol? Be sure your answer has the
volume

A 8.0-fl oz bottle of orange extract contains 1.0 x 10- mL of ethanol. What is the
correct number of significant figures.
Note: Reference the Conversion factors for non-SI units table for additional information.

Answers

GPT 3.5
To find the percent concentration of ethanol in the orange extract, we need to calculate the volume percent.

Volume percent = (volume of ethanol / total volume) x 100%

Converting 8.0 fluid ounces to milliliters:
1 fluid ounce = 29.5735 milliliters
8.0 fluid ounces = 8.0 x 29.5735 = 236.588 milliliters

Percent concentration of ethanol = (1.0 x 10^-2 mL / 236.588 mL) x 100%
Percent concentration of ethanol = (1.0 x 10^-2 / 236.588) x 100%
Percent concentration of ethanol = (0.00001 / 236.588) x 100%
Percent concentration of ethanol ≈ 0.0000422 x 100%
Percent concentration of ethanol ≈ 0.00422%

Therefore, the percent concentration of ethanol in the orange extract is approximately 0.00422%. The correct number of significant figures is 3, as the volume of ethanol is given with three significant figures.