If p square q square (p+q)(p-q), Evaluate (121) square -(79) square

Answer 1

To evaluate (121)^2 - (79)^2, we can use the formula for the difference of squares, which states that (a^2 - b^2) = (a + b)(a - b).

So, in this case, we have (121)^2 - (79)^2 = (121 + 79)(121 - 79).

Calculating the values inside the parentheses, we get:

(121 + 79) = 200
(121 - 79) = 42

Therefore, (121)^2 - (79)^2 = 200 * 42 = 8400.

Therefore, the value of (121)^2 - (79)^2 is 8400.