Question
Starting from rest Maria pulls horizontally on her new wagon for 1.1 seconds. She exerts a constant force of 89N against a frictional force of 43N. The wagon's final velocity is 3.2m/s. If she is on a level ground, how much does the wagon weigh?
Answers
bobpursley
Fnet= m a= m *3.2/1.1
89-43=m * 3.2/1.1 solve for m
weight= mg
89-43=m * 3.2/1.1 solve for m
weight= mg
Use the fact that impulse
= (net force)*(time) = (momentum change)
The momentum given to the wagon is
(89 - 43)* 1.1 = 50.5 kg m/s
Divide that by the final velocity to get the mass in kg.
= (net force)*(time) = (momentum change)
The momentum given to the wagon is
(89 - 43)* 1.1 = 50.5 kg m/s
Divide that by the final velocity to get the mass in kg.
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