Question
If the gas diffuse at a rate of one half as faster as oxygen, find the molecular mass of the gas?
Answers
GPT 3.5
Let the molecular mass of the gas be M.
The rate of diffusion of a gas is inversely proportional to the square root of its molecular mass.
Therefore, the rate of diffusion of the gas = 1/sqrt(M)
Given that the gas diffuses at a rate one half as fast as oxygen, we have:
(1/sqrt(M))/(1/sqrt(32)) = 1/2
sqrt(32)/sqrt(M) = 1/2
sqrt(32) = sqrt(M)*2
M = (sqrt(32))^2
M = 32
Therefore, the molecular mass of the gas is 32.
The rate of diffusion of a gas is inversely proportional to the square root of its molecular mass.
Therefore, the rate of diffusion of the gas = 1/sqrt(M)
Given that the gas diffuses at a rate one half as fast as oxygen, we have:
(1/sqrt(M))/(1/sqrt(32)) = 1/2
sqrt(32)/sqrt(M) = 1/2
sqrt(32) = sqrt(M)*2
M = (sqrt(32))^2
M = 32
Therefore, the molecular mass of the gas is 32.