To find the molar mass of geraniol, we can use the ideal gas law equation:
PV = nRT
Where:
P = Pressure = 103 torr = 103/760 atm
V = Volume = 1 L
n = moles of substance
R = ideal gas constant = 0.0821 L.atm/mol.K
T = Temperature = 260 degrees Celsius = 533 K
Rearranging the equation to solve for n:
n = PV / RT
n = (103/760) * 1 / (0.0821 * 533)
n = 0.000281 moles
Now, we can find the molar mass of geraniol using the formula:
Molar mass = mass / moles
Given that the density of the vapor at 260 degrees Celsius and 103 torr is 0.48 g per liter, we can calculate the mass of 1 liter of the vapor:
Mass = Density * Volume
Mass = 0.48 g/L * 1 L
Mass = 0.48 g
Molar mass = 0.48 g / 0.000281 mol
Molar mass ≈ 1702.85 g/mol
Therefore, the molar mass of geraniol is approximately 1702.85 g/mol.
The volatile organic compound gereniol , a component of oil in rose ,is used in perfumery . The density of the vapour is at 260 degrees Celsius and 103 toor is 0.48 g per litre . What is the molar mass of geraniol?
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