Question

Compute the average (mean) from the data shown. (round to the nearest tenth)

{91 , 91 , 91 , 97 , 65 , 37 , 41 , 76 , 87}
Responses
A 74.274.2
B 74.974.9
C 75.175.1
D 75.4

Answer 1

The average (mean) is calculated by adding up all the numbers and then dividing by the total number of numbers.

(91 + 91 + 91 + 97 + 65 + 37 + 41 + 76 + 87) / 9 = 676 / 9 = 75.1

Therefore, the average is 75.1, rounded to the nearest tenth.

The answer is C) 75.1.

Answer 2

Effects of Inserting Data III
Consider this data set.

92, 76, 58, 84
Question 1
What is the mean of the given data?
Responses
A 68.268.2
B 77.577.5
C 81.481.4
D 83.283.2
Question 2
After inserting an additional data value (x), the mean decreases to 74. Which number could be the inserted x value?
Responses
A 5858
B 6060
C 6868
D 7070

Answer 3

For the given data set {92, 76, 58, 84}, the mean is calculated by adding up all the numbers and dividing by the total number of numbers.

(92 + 76 + 58 + 84) / 4 = 310 / 4 = 77.5

So, the mean of the given data is 77.5.

Now, to find the value of x that when added to the data set will reduce the mean to 74, we can set up an equation:

(92 + 76 + 58 + 84 + x) / 5 = 74
(310 + x) / 5 = 74
310 + x = 370
x = 60

Therefore, the inserted value x is 60, so the answer is B) 60.

So, for the responses:
Question 1: B) 77.5
Question 2: B) 60

Answer 4

The number of absences 15 students had last year are shown below.




0, 1, 1, 2, 2, 4, 6, 8, 10, 10, 12, 14, 16, 17, 18

Which box and whisker plot best represents these data?
Responses
A
Student Absences

Student Absences Image with alt text:
B
Student Absences

Student Absences Image with alt text:
C
Student Absences

Student Absences Image with alt text:
D
Student Absences

Answer 5

Based on the data provided for the number of absences 15 students had last year:

0, 1, 1, 2, 2, 4, 6, 8, 10, 10, 12, 14, 16, 17, 18

The box plot that best represents these data is the one with the following characteristics:
- The minimum value corresponds to 0
- The lower quartile is around 2
- The median is around 8
- The upper quartile is around 14
- The maximum value is around 18
- There are possible outliers around 16 and 17

Looking at the characteristics described above, the box plot that best fits this data is Option B.

Therefore, the response is:
B. Student Absences for the box and whisker plot that best represents the data provided.