A baseball is thrown with a velocity of 80ft/sec at angle of 30 above the horizontal .it's maximum height will be?

Answer 1

To find the maximum height of the baseball, we need to first calculate the time it takes to reach the maximum height.

The vertical component of the initial velocity is given by:
Vy = V0*sin(θ)
Vy = 80*sin(30)
Vy = 40 ft/sec

To find the time it takes to reach the maximum height, we can use the following kinematic equation:
Vy = Vy0 - gt

where g is the acceleration due to gravity (32 ft/sec^2).

0 = 40 - 32t
t = 40/32
t = 1.25 sec

Now, we can find the maximum height using the following formula:
h = Vy0*t - 0.5*g*t^2

h = 40*1.25 - 0.5*32*(1.25)^2
h = 50 - 0.5*32*1.5625
h = 50 - 25
h = 25 ft

Therefore, the maximum height of the baseball will be 25 feet.