Question

Use the table to answer the question.

Number of White Balls Selected Number of Red Balls Selected
Bowl A 45 55
Bowl B 60 40
Bowls A and B contain a number of white and red balls. Clark repeatedly selected a ball from both bowls and recorded the results in a table. If there are 500 balls in Bowl B, what is the estimated difference in the expected number of white and red balls in Bowl B

Answer 1

u sure

Answer 2

To find the estimated difference in the expected number of white and red balls in Bowl B, we first need to calculate the expected number of white balls and red balls in Bowl B separately.

From the table, we can see that in Bowl B, the proportion of white balls selected is 60/(60+40) = 0.6 and the proportion of red balls selected is 40/(60+40) = 0.4.

Since there are 500 balls in Bowl B, we can estimate the number of white balls in Bowl B as 0.6 * 500 = 300 and the number of red balls in Bowl B as 0.4 * 500 = 200.

Therefore, the estimated difference in the expected number of white and red balls in Bowl B is 300 (number of white balls) - 200 (number of red balls) = 100.

Answer 3

I apologize for the mistake in my previous response. Let me correct it:

From the table, we can see that out of the balls selected from Bowl B, 60% were white and 40% were red. Since there are 500 balls in Bowl B, we can estimate the number of white balls in Bowl B as 0.60 * 500 = 300 and the number of red balls in Bowl B as 0.40 * 500 = 200.

Therefore, the estimated difference in the expected number of white and red balls in Bowl B is 300 (number of white balls) - 200 (number of red balls) = 100.

So, the estimated difference in the expected number of white and red balls in Bowl B is 100.