A: To find the least number of meals needed to make a profit, we need to set P greater than zero and solve for x.
2x^2 - 44x - 150 > 0
Solving this quadratic inequality, we find x > 15.82. Since Amelia cannot cater a fraction of a meal, she would need to cater at least 16 meals to make a profit.
B: If she caters no meals one week, the profit would be:
P = 2(0)^2 - 44(0) - 150
P = -150
So, she would lose $150 that week.
C: To find her profit for catering 50 meals, we substitute x = 50 into the profit function:
P = 2(50)^2 - 44(50) - 150
P = 2000 - 2200 - 150
P = -350
Therefore, her profit for catering 50 meals is -$350.
Amelia runs a catering business. Based on her records, her weekly profit can be approximated by P=2x^2-44z-150, where x is the number of meats she caters and P is her profit. When P is negative, Amelia has lost money.
A: What is the least number of meals Amelia needs to cater in order to make a profit?
B: If she caters no meals one week, how much money does she lose?
C: What is her profit for catering 50 meals?
1 answer