Asked by Anonymous
Solve these equations for x by factoring:
1) x(x-4)=12
2) 2x^3+50x=20x^2
3) 2x^2+x-6=0
Thank you for all your help!!!!
1) x(x-4)=12
2) 2x^3+50x=20x^2
3) 2x^2+x-6=0
Thank you for all your help!!!!
Answers
Answered by
bobpursley
Pre calculus? This is stock Algebra II.
put the equations in the form of
ax^2+bx+c=0 then factor.
for instance, c is already in that form.
2x^2+x-6=0
(2x-3)(x+2)=0
x= 3/2 x=-2
do the others the same method.
put the equations in the form of
ax^2+bx+c=0 then factor.
for instance, c is already in that form.
2x^2+x-6=0
(2x-3)(x+2)=0
x= 3/2 x=-2
do the others the same method.
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