A stone of 5g is projected through a rubber catapult. If it is stretche through a distance of 7 cm by an average force of 70N calculate the velocity of the stone when released. Theory W=mg=ke

1 answer

First, we need to calculate the work done by the rubber catapult on the stone as it is stretched through a distance of 7 cm.

Work (W) = Force (F) x Distance (d)
W = 70N x 0.07m
W = 4.9 J

Since the work done on the stone is equal to the kinetic energy it gains, we can use the formula for kinetic energy to find the velocity of the stone.

Kinetic Energy (KE) = 0.5 x mass x velocity^2
4.9J = 0.5 x 0.005kg x v^2
4.9 = 0.0025v^2
v^2 = 4.9 / 0.0025
v^2 = 1960
v = √1960
v ≈ 44.27 m/s

Therefore, the velocity of the stone when released from the rubber catapult is approximately 44.27 m/s.