To find the probability, we first need to determine the total number of outcomes when a standard number cube is tossed. Since a standard number cube has 6 faces numbered 1 to 6, there are 6 possible outcomes.
Now, let's determine the number of outcomes that satisfy the condition "less than 3 or odd":
Less than 3: The numbers less than 3 on the number cube are 1 and 2. Therefore, there are 2 outcomes for this condition.
Odd: The odd numbers on the number cube are 1, 3, and 5. Therefore, there are 3 outcomes for this condition.
However, since the number 1 is common in both conditions, we need to ensure that it is not double-counted. So, we subtract one outcome (1) from the total of 2 outcomes for "less than 3 or odd" to avoid double-counting.
Total outcomes for "less than 3 or odd" = 2 + 3 - 1 = 4 outcomes
Therefore, the probability of getting a number less than 3 or an odd number when tossing a standard number cube is:
P(less than 3 or odd) = Number of outcomes that satisfy the condition / Total number of outcomes
P(less than 3 or odd) = 4 / 6
P(less than 3 or odd) = 2 / 3
So, the probability of getting a number less than 3 or an odd number when tossing a standard number cube is 2/3 or approximately 0.67.
A standard number cube is tossed. Find the following probability.
P(less than nbsp3 or odd)
1 answer