Question
A standard number cube is tossed. Find the following probability.
P(less than nbsp3 or odd)
P(less than nbsp3 or odd)
Answers
GPT 3.5
To find the probability, we first need to determine the total number of outcomes when a standard number cube is tossed. Since a standard number cube has 6 faces numbered 1 to 6, there are 6 possible outcomes.
Now, let's determine the number of outcomes that satisfy the condition "less than 3 or odd":
Less than 3: The numbers less than 3 on the number cube are 1 and 2. Therefore, there are 2 outcomes for this condition.
Odd: The odd numbers on the number cube are 1, 3, and 5. Therefore, there are 3 outcomes for this condition.
However, since the number 1 is common in both conditions, we need to ensure that it is not double-counted. So, we subtract one outcome (1) from the total of 2 outcomes for "less than 3 or odd" to avoid double-counting.
Total outcomes for "less than 3 or odd" = 2 + 3 - 1 = 4 outcomes
Therefore, the probability of getting a number less than 3 or an odd number when tossing a standard number cube is:
P(less than 3 or odd) = Number of outcomes that satisfy the condition / Total number of outcomes
P(less than 3 or odd) = 4 / 6
P(less than 3 or odd) = 2 / 3
So, the probability of getting a number less than 3 or an odd number when tossing a standard number cube is 2/3 or approximately 0.67.
Now, let's determine the number of outcomes that satisfy the condition "less than 3 or odd":
Less than 3: The numbers less than 3 on the number cube are 1 and 2. Therefore, there are 2 outcomes for this condition.
Odd: The odd numbers on the number cube are 1, 3, and 5. Therefore, there are 3 outcomes for this condition.
However, since the number 1 is common in both conditions, we need to ensure that it is not double-counted. So, we subtract one outcome (1) from the total of 2 outcomes for "less than 3 or odd" to avoid double-counting.
Total outcomes for "less than 3 or odd" = 2 + 3 - 1 = 4 outcomes
Therefore, the probability of getting a number less than 3 or an odd number when tossing a standard number cube is:
P(less than 3 or odd) = Number of outcomes that satisfy the condition / Total number of outcomes
P(less than 3 or odd) = 4 / 6
P(less than 3 or odd) = 2 / 3
So, the probability of getting a number less than 3 or an odd number when tossing a standard number cube is 2/3 or approximately 0.67.