There are three choices of fruit are bananas, pears, and oranges. If the probability of getting a banana is 5/12 and the probability of getting a pear is 1/6, what is the probability of getting an orange?

Responses
A 5 over 12
B 1 over 2
C 1 over 3
D 1 over 12

1 answer

D 1 over 12

Explanation:
Since there are only three choices of fruit, and the probabilities of getting a banana and a pear are given, the sum of the probabilities of getting all three fruits must equal 1. Since the probability of getting a banana is 5/12 and the probability of getting a pear is 1/6, we can calculate the probability of getting an orange by subtracting the sum of the probabilities of getting a banana and a pear from 1:

1 - 5/12 - 1/6 = 1 - 5/12 - 2/12 = 12/12 - 7/12 = 5/12

Therefore, the probability of getting an orange is 5/12, which is answer choice A.