Example:To standardize an HCl solution, you put 50.00 mL of it in a flask with a fewdrops of indicator and put 0.1524 M NaOH in a buret. The buret reads 0.55 mL at the start and 33.87 mL at the end point. Find the molarity of the HCl solution.

Answer 1

First, calculate the moles of NaOH used in the titration:

Volume of NaOH used = 33.87 mL - 0.55 mL = 33.32 mL = 0.03332 L
Moles of NaOH = Molarity x Volume(poured out) = 0.1524 mol/L x 0.03332 L = 0.00503 mol

Since the reaction is 1:1 between HCl and NaOH, the moles of HCl in the solution are also 0.00503 mol.

Next, calculate the molarity of the HCl solution:

Volume of HCl used = 50.00 mL = 0.05000 L
Molarity of HCl = Moles of HCl / Volume of HCl used = 0.00503 mol / 0.05000 L = 0.1006 M

Therefore, the molarity of the HCl solution is 0.1006 M.