Question
Example:To standardize an HCl solution, you put 50.00 mL of it in a flask with a fewdrops of indicator and put 0.1524 M NaOH in a buret. The buret reads 0.55 mL at the start and 33.87 mL at the end point. Find the molarity of the HCl solution.
Answers
GPT 3.5
First, calculate the moles of NaOH used in the titration:
Volume of NaOH used = 33.87 mL - 0.55 mL = 33.32 mL = 0.03332 L
Moles of NaOH = Molarity x Volume(poured out) = 0.1524 mol/L x 0.03332 L = 0.00503 mol
Since the reaction is 1:1 between HCl and NaOH, the moles of HCl in the solution are also 0.00503 mol.
Next, calculate the molarity of the HCl solution:
Volume of HCl used = 50.00 mL = 0.05000 L
Molarity of HCl = Moles of HCl / Volume of HCl used = 0.00503 mol / 0.05000 L = 0.1006 M
Therefore, the molarity of the HCl solution is 0.1006 M.
Volume of NaOH used = 33.87 mL - 0.55 mL = 33.32 mL = 0.03332 L
Moles of NaOH = Molarity x Volume(poured out) = 0.1524 mol/L x 0.03332 L = 0.00503 mol
Since the reaction is 1:1 between HCl and NaOH, the moles of HCl in the solution are also 0.00503 mol.
Next, calculate the molarity of the HCl solution:
Volume of HCl used = 50.00 mL = 0.05000 L
Molarity of HCl = Moles of HCl / Volume of HCl used = 0.00503 mol / 0.05000 L = 0.1006 M
Therefore, the molarity of the HCl solution is 0.1006 M.