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To solve this problem, we first need to determine the stoichiometry of the reaction. From the balanced chemical equation, we can see that 2 moles of Cu2S produces 2 moles of SO2.
Therefore, 1 mole of Cu2S produces 1 mole of SO2.
Given that 10.0 mol. of Cu2S reacts,
10.0 mol. Cu2S x (1 mol. SO2 / 1 mol. Cu2S) = 10.0 mol. SO2
Now we need to convert the moles of SO2 to grams:
10.0 mol SO2 x (64.06 g / 1 mol) = 640.6 g
Therefore, 640.6 grams of sulfur dioxide are formed when 10.0 mol of copper(I) sulfide reacts.